Mysql-多个left join 计算逻辑

单个left join:

(1)一对一:结果表的行数=左表行数

(2)一对多:结果表的行数>左表行数

多个left join:

(0)多个left join由上到下,依次生成查询表,原理同单个left join

(1)需要补充的是,如果在left join a表之前,想先对a表做一个字段的筛选,不能在多个left join之后用where来条件过滤,因为,多个left join是优先于where执行的,如果用where是对多个left join之后的结果查询表进行的条件过滤。(这种很容造成结果错误,也就是结果数据不全)

应该用,left join ON 后+"and"去先过滤

a left join b ON a.id=b.id and a.isdel =0 b.status =1

   left join c ON a.id =c.id and c.type=3

PS:有时候,单个left join、多个left join 需要跟select配合套多个"select马甲"使用,下边是一个很不错的常用模版套法:

(一般对于不知道什么时候起别名 什么时候用括号的老铁们 真实头疼  所以发个模板,可以根据自己的需求,进行套用)

https://www.cnblogs.com/LHWorldBlog/p/7753914.html

不多说 直接上语句   
SELECT
    a.id,
    a.thumbNail,
    a. NAME,
    a.marketPrice,
    a.memberPrice,
    a.personName,
    a. STATUS,
    a.recieveOrderDate,
    a.trackNumber,
    a.contact,
    a.reportSendDate,
    b.trackNumber,
    a.reportDownloadPath
FROM
    (
        SELECT
            od.id,
            ps.thumbNail,
            ps. NAME,
            od.marketPrice,
            od.memberPrice,
            od.personName,
            od. STATUS,
            od.recieveOrderDate,
            ol.trackNumber,
            ol.contact,
            od.reportSendDate,
            od.reportSendOrderLogisticId,
            od.reportDownloadPath
        FROM
            orders.order_detail od
        LEFT JOIN orders.order_logistics ol ON od.recieveOrderLogisticId = ol.id
        LEFT JOIN orders.product_snapshot ps ON od.productSnapShotId = ps.id
        WHERE
            od.valid = TRUE
        AND ol.valid = TRUE
        AND od.orderId =?
    ) a
LEFT JOIN (
    SELECT
        ol.trackNumber,
        od.id
    FROM
        orders.order_detail od
    LEFT JOIN orders.order_logistics ol ON od.reportSendOrderLogisticId = ol.id
    WHERE
        od.valid = TRUE
    AND ol.valid = TRUE
    AND od.orderId =?
) b ON a.id = b.id
生活其实也很简单,喜欢的就去争取、得到的就珍惜、失去的就忘记。
原文地址:https://www.cnblogs.com/Formulate0303/p/13992755.html