P2023 [AHOI2009] 维护序列

链接:Miku


和[线段树2](https://www.luogu.com.cn/problem/P3373)

一样的题

#include<iostream>
#include<cstdio>
#include<algorithm>
#include<cstring>
#define int long long 
using namespace std;
int n,mod;
int tree[400001];
int lazya[400001],lazym[400001];
int m;
int sum[400001];
int f,t,g,c; 
void pushup(int x){
	sum[x]=sum[x<<1]%mod+sum[x<<1|1]%mod;
	sum[x]%=mod;
	return ; 
} 
void pushdown(int x,int l,int r){
	if(lazym[x]!=1){
		lazym[x<<1]*=lazym[x]%mod;lazym[x<<1|1]*=lazym[x]%mod;
		lazym[x<<1]%=mod;lazym[x<<1|1]%=mod;
		sum[x<<1]*=lazym[x]%mod;sum[x<<1|1]*=lazym[x]%mod;
		sum[x<<1]%=mod;sum[x<<1|1]%=mod;
		lazya[x<<1]*=lazym[x]%mod;lazya[x<<1|1]*=lazym[x]%mod;
		lazya[x<<1]%=mod;lazya[x<<1|1]%=mod;
		lazym[x]=1;
	}
	if(lazya[x]){
		int mid=(l+r)>>1;
		lazya[x<<1]+=lazya[x]%mod;lazya[x<<1|1]+=lazya[x]%mod;
		sum[x<<1]+=lazya[x]*(mid-l+1);
		sum[x<<1]%=mod;
		sum[x<<1|1]+=lazya[x]*(r-mid);
		sum[x<<1|1]%=mod;
		lazya[x<<1]%=mod;lazya[x<<1|1]%=mod;
		lazya[x]=0;
	}
	return ;
}
void update1(int x,int l,int r,int L,int R,int ad){
	if(L<=l&&r<=R){
		lazya[x]+=ad;
		lazya[x]%=mod;
		sum[x]+=(r-l+1)*ad;
		sum[x]%=mod;
		return ; 
	}
	pushdown(x,l,r);
	int mid=(r+l)>>1;
	if(L<=mid) update1(x<<1,l,mid,L,R,ad);
	if(R>mid) update1(x<<1|1,mid+1,r,L,R,ad);
	pushup(x);
	return ;	
}
void update2(int x,int l,int r,int L,int R,int ad){
	if(L<=l&&r<=R){
		lazym[x]*=ad;
		lazym[x]%=mod;
		lazya[x]*=ad;
		lazya[x]%=mod;
		sum[x]*=ad;
		sum[x]%=mod;
		return ; 
	}
	pushdown(x,l,r);
	int mid=(r+l)>>1;
	if(L<=mid) update2(x<<1,l,mid,L,R,ad);
	if(R>mid) update2(x<<1|1,mid+1,r,L,R,ad);
	pushup(x);
	return ;	
}
int query(int x,int l,int r,int L,int R){
	if(L<=l&&r<=R){
		return sum[x]%=mod;
	}
	pushdown(x,l,r);
	int mid=(r+l)>>1;
	int ans=0;
	if(L<=mid) ans+=query(x<<1,l,mid,L,R),ans%=mod;
	if(R>mid) ans+=query(x<<1|1,mid+1,r,L,R),ans%=mod;
	return ans%=mod;
} 
signed main(){
	scanf("%lld%lld",&n,&mod);
	for(int i=1;i<=400001;++i)
	lazym[i]=1;
	for(int i=1;i<=n;++i){
		scanf("%lld",&m);
		update1(1,1,n,i,i,m);
	}
	scanf("%lld",&m);
	for(int i=1;i<=m;++i){
		scanf("%lld",&f);
		if(f==2){
			scanf("%lld%lld%lld",&t,&g,&c);
			update1(1,1,n,t,g,c);
		}
		if(f==1){
			scanf("%lld%lld%lld",&t,&g,&c);
			update2(1,1,n,t,g,c);
		}
		if(f==3){
			scanf("%lld%lld",&t,&g);
			cout<<query(1,1,n,t,g)%mod<<endl;;
		}
	} 
	return 0;
} 
原文地址:https://www.cnblogs.com/For-Miku/p/13658324.html