Java 【Exception】查看异常出现在具体的文件名/类名/方法名/具体行号

try{
            Integer adminID = Integer.parseInt(adminId);
            XxAdmin admin = adminRepository.findOne(adminID);
            model.addAttribute("admin",admin);
        }catch (Exception e){
            StackTraceElement stackTraceElement = e.getStackTrace()[0];
            String errorMsg = "文件名："+stackTraceElement.getFileName()+
                            "
类名："+stackTraceElement.getClassName()+
                            "
方法名："+stackTraceElement.getMethodName()+
                            "
抛出异常行号："+stackTraceElement.getLineNumber()+
                            "
异常信息："+ e.getMessage();
            System.out.println(errorMsg);
            logger.error(errorMsg);
        }