估值线段树

#include<cmath>
#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<iostream>
#include<algorithm>
# define maxn 1010
using namespace std;
typedef long long LL;
int n,m;
struct node{
    LL a,b,c;
}g[maxn];
struct Tree{
    LL a,mxb,mnb,c;
}tr[4*maxn];
 
int sc=0;
LL Max(LL a,LL b){return a>b? a:b;}
LL Min(LL a,LL b){return a<b? a:b;}
void pushup(int rt){
    int ls=rt<<1, rs=rt<<1|1;
    tr[rt].a=Max(tr[ls].a,tr[rs].a);
    tr[rt].mnb=Min(tr[ls].mnb,tr[rs].mnb);
    tr[rt].mxb=Max(tr[ls].mxb,tr[rs].mxb);
    tr[rt].c=Max(tr[ls].c,tr[rs].c);
}
void bds(int rt,int l,int r){
    if(l==r){
        tr[rt].a=g[l].a; tr[rt].mxb=tr[rt].mnb=g[l].b; tr[rt].c=g[l].c;
        return;
    }
    int mid=(l+r)>>1;
    bds(rt<<1,l,mid);
    bds(rt<<1|1,mid+1,r);
    pushup(rt);
}
LL ans;
void zheng_find(int rt,int l,int r,LL x,LL y){
    if(l==r){
        ans=Max(ans,tr[rt].a*x+tr[rt].mxb*y+tr[rt].c);
        return;
    }
    int mid=(l+r)>>1,ls=rt<<1,rs=rt<<1|1;
    LL ans1=tr[ls].a*x+tr[ls].mxb*y+tr[ls].c;
    LL ans2=tr[rs].a*x+tr[rs].mxb*y+tr[rs].c;
    if(ans1 > ans2) {
        if(ans>ans1) return;
        zheng_find(rt<<1,l,mid,x,y);
        if(ans<ans2) zheng_find(rt<<1|1,mid+1,r,x,y);
    }
    else{
        if(ans>ans2) return;
        zheng_find(rt<<1|1,mid+1,r,x,y);
        if(ans<ans1) zheng_find(rt<<1,l,mid,x,y);
    }
}
void fu_find(int rt,int l,int r,LL x,LL y){
    if(l==r){
        ans=Max(ans,tr[rt].a*x+tr[rt].mnb*y+tr[rt].c);
        return;
    }
    int mid=(l+r)>>1,ls=rt<<1,rs=rt<<1|1;
    LL ans1=tr[ls].a*x+tr[ls].mnb*y+tr[ls].c;
    LL ans2=tr[rs].a*x+tr[rs].mnb*y+tr[rs].c;
    if(ans1 > ans2){
        if(ans>ans1) return;
        fu_find(rt<<1,l,mid,x,y);
        if(ans < ans2) fu_find(rt<<1|1,mid+1,r,x,y);
    }
    else {
        if(ans>ans2) return;
        fu_find(rt<<1|1,mid+1,r,x,y);
        if(ans < ans1) fu_find(rt<<1,l,mid,x,y);
    }
}
int main(){
    //freopen("function.in","r",stdin);
    //freopen("function.out","w",stdout);
    scanf("%d%d",&n,&m);
    for(int i=1;i<=n;i++) scanf("%lld%lld%lld",&g[i].a,&g[i].b,&g[i].c);
    bds(1,1,n);
    LL x;
    for(int i=1;i<=m;i++){
        scanf("%lld",&x);
        ans=-0x7fffffffffffffffLL;
        if(x>=0) zheng_find(1,1,n,x*x,x);
        else fu_find(1,1,n,x*x,x);
        printf("%lld
",ans);
    }
    return 0;
}