LC 1723. Find Minimum Time to Finish All Jobs (dp+二分)

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普通dp:

class Solution {
public:
    int n;
    int minimumTimeRequired(vector<int>& jobs, int k) {
        n=jobs.size();
        vector<int> sum(1<<n);
        for(int i=1;i<(1<<n);i++){
            for(int j=0;j<n;j++){
                if(i&(1<<j)){
                    sum[i]=sum[i-(1<<j)]+jobs[j];
                    break;
                }
            }
        }
        vector<vector<int>> dp(k,vector<int>(1<<n, INT_MAX));
        for(int i=0;i<(1<<n);i++) dp[0][i]=sum[i];

        for(int i=1;i<k;i++){
            for(int j=0;j<(1<<n);j++){
                if(j==0){
                    dp[i][j]=0;
                    continue;
                }
                for(int k=j;k>0;k=((k-1)&j)){
                    dp[i][j]=min(dp[i][j],max(sum[k],dp[i-1][j-k]));
                }
            }
        }
        return dp[k-1][(1<<n)-1];
    }

    
};

二分:

class Solution {
public:
    int n;
    int minimumTimeRequired(vector<int>& jobs, int k) {
        n=jobs.size();
        vector<int> sum(1<<n);
        for(int i=1;i<(1<<n);i++){
            for(int j=0;j<n;j++){
                if(i&(1<<j)){
                    sum[i]=sum[i-(1<<j)]+jobs[j];
                    break;
                }
            }
        }
        int left=0;
        int right=0;
        for(int i:jobs){
            left=max(left,i);
            right+=i;
        }
        while(left<=right){
            int mid=left+(right-left)/2;
            int workers=helper(mid,sum);
            if(workers<=k) right=mid-1;
            else left=mid+1;
        }
        return left;
    }

    int helper(int limit, vector<int>& sum){
        vector<int> dp(1<<n,INT_MAX);
        dp[0]=0;
        for(int i=1;i<(1<<n);i++){
            for(int j=i;j>0;j= ((j-1)&i)){
                if(sum[j]<=limit) dp[i]=min(dp[i],1+dp[i-j]);
            }
        }
        return dp[(1<<n)-1];
    }
};
原文地址:https://www.cnblogs.com/FEIIEF/p/14263704.html