Leetcode: Shuffle an Array

Shuffle a set of numbers without duplicates.

Example:

// Init an array with set 1, 2, and 3.
int[] nums = {1,2,3};
Solution solution = new Solution(nums);

// Shuffle the array [1,2,3] and return its result. Any permutation of [1,2,3] must equally likely to be returned.
solution.shuffle();

// Resets the array back to its original configuration [1,2,3].
solution.reset();

// Returns the random shuffling of array [1,2,3].
solution.shuffle();

Random random = new Random();

random.nextInt(int i);

 1 public class Solution {
 2     int[] arr;
 3     Random random;
 4     
 5 
 6     public Solution(int[] nums) {
 7         arr = nums;
 8         random = new Random();
 9     }
10     
11     /** Resets the array to its original configuration and return it. */
12     public int[] reset() {
13         return arr;
14     }
15     
16     /** Returns a random shuffling of the array. */
17     public int[] shuffle() {
18         int[] copy = arr.clone();
19         
20         for (int i=arr.length-1; i>=0; i--) {
21             int index = random.nextInt(i+1);
22             int temp = copy[index];
23             copy[index] = copy[i];
24             copy[i] = temp;
25         }
26         return copy;
27     }
28 }
29 
30 /**
31  * Your Solution object will be instantiated and called as such:
32  * Solution obj = new Solution(nums);
33  * int[] param_1 = obj.reset();
34  * int[] param_2 = obj.shuffle();
35  */
原文地址:https://www.cnblogs.com/EdwardLiu/p/6112675.html