Django Ajax提交数据请求

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
</head>
<body>
<input type="button" onclick="AjaxSubmit()" value="Ajax提交">
<script src="jquery.min.js"></script>
<script>
function AjaxSubmit() {
var host = "1.1.1.1";
var port = "9999";
$.ajax(
{
url:"/ajax_data/",
type:"POST",
data:{h:host,p:port},
sucess:function (arg) {

}
}
);
}
</script>
</body>
</html>
原文地址:https://www.cnblogs.com/Devopser/p/6298076.html