问题 E: Jack的A+B

时间限制: 1 Sec 内存限制: 128 MB
提交: 1996 解决: 601
[提交] [状态] [命题人:jsu_admin]

题目描述

现在有整数a,b，请按西方数字数量级方式输出a+b

输入

题目有多组测试数据
每组输入两个整数a，b
(0<=a,b<=10000000)

输出

输出西方数字数量级的a+b

样例输入 Copy

999 1
36 30
100000 100

样例输出 Copy

1,000
66
100,100

提示

输出的数从最低位起，每三位用逗号隔开

倒着模拟题意即可，每三位输出一个逗号，注意和为 0 的情况

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #include<string.h>
 4  void int2str(int n, char *str)    {
 5         char buf[10] = "";
 6         int i = 0;
 7         int len = 0;
 8         int temp = n < 0 ? -n: n;  // temp为n的绝对值
 9  
10        if (str == NULL)
11        {
12            return;
13       }
14       while(temp)
15        {
16            buf[i++] = (temp % 10) + '0';  //把temp的每一位上的数存入buf
17            temp = temp / 10;
18        }
19   
20        len = n < 0 ? ++i: i;  //如果n是负数，则多需要一位来存储负号
21        str[i] = 0;            //末尾是结束符0
22        while(1)
23        {
24            i--;
25            if (buf[len-i-1] ==0)
26            {
27                break;
28            }
29            str[i] = buf[len-i-1];  //把buf数组里的字符拷到字符串
30        }
31        if (i == 0 )
32        {
33            str[i] = '-';          //如果是负数，添加一个负号
34       }
35    }
36 
37 int main(){
38     int a,b;
39     int sum;
40     char num[1000];
41     while(scanf("%d%d",&a,&b)!=EOF){
42     memset(num,0,sizeof(num));
43     sum = a+b;
44     if(sum ==0)
45     {
46         printf("0
");
47         continue;
48     }
49     int k =0;
50     int2str(sum,num);
51     //printf("%s",num); 
52     int h = strlen(num)%3;
53     if(h!=0){
54     
55     for(int i= 0;i<h;i++)
56     {
57         printf("%c",num[i]);
58     }
59     if(strlen(num)>3)
60     printf(",");
61     }
62 //    int k = 0;
63     for(int i = h;i<strlen(num);i++)
64     {
65         
66         printf("%c",num[i]);
67         k++;
68         if(k%3==0&&i!=strlen(num)-1&&k!=strlen(num)){
69             printf(",");
70         }
71     }
72     printf("
");
73 }
74 }

View Code

 1 /*
 2 *@Author:   STZG
 3 *@Language: C++
 4 */
 5 #include <bits/stdc++.h>
 6 #include<iostream>
 7 #include<algorithm>
 8 #include<cstdlib>
 9 #include<cstring>
10 #include<cstdio>
11 #include<string>
12 #include<vector>
13 #include<bitset>
14 #include<queue>
15 #include<deque>
16 #include<stack>
17 #include<cmath>
18 #include<list>
19 #include<map>
20 #include<set>
21 //#define DEBUG
22 #define RI register int
23 using namespace std;
24 typedef long long ll;
25 //typedef __int128 lll;
26 const int N=10000;
27 const int MOD=1e9+7;
28 const double PI = acos(-1.0);
29 const double EXP = 1E-8;
30 const int INF = 0x3f3f3f3f;
31 int t,n,m,k,q;
32  
33 int main()
34 {
35 #ifdef DEBUG
36     freopen("input.in", "r", stdin);
37     //freopen("output.out", "w", stdout);
38 #endif
39     while(scanf("%d%d",&n,&m)!=EOF){
40         t=n+m;
41         string ans;
42         k=0;
43         while(t){
44             k++;
45             q=t%10;
46             ans=(char)('0'+q)+ans;
47             t/=10;
48             if(t&&k>=3){
49                 k=0;
50                 ans=','+ans;
51             }
52         }
53         if(n+m<0)
54             ans='-'+ans;
55         if(n+m==0)
56             ans='0'+ans;
57         cout<<ans<<endl;
58     }
59  
60     //cout << "Hello world!" << endl;
61     return 0;
62 }

View Code