Java蓝桥杯--入门训练(3)序列求和

关键词:入门求和公式

题目:

解决方案:
方法一:(小丽丽)

 1 import java.util.Scanner;
 2 
 3 public class Main {
 4 
 5         public static void main(String[] args) {
 6             Scanner in = new Scanner(System.in);
 7             long n = in.nextLong();
 8             long sum = 0;
 9 /*
10         for (long i = 1; i <= n; i++) {
11             sum += i;
12         }
13 */
14             sum = (1 + n) * n / 2;
15             System.out.println(sum);
16         }
17 
18 }

方法二(朕):

 1 import java.util.Scanner;
 2 
 3 public class Main {
 4     public static void main(String[] args){
 5 
 6      //   System.out.println("题目:求1+2+3+...+n的值");
 7         Scanner read =new Scanner(System.in);
 8       //  System.out.println("
请输入您要计算的n的值:");
 9         long n=read.nextLong();
10         long answer=0;
11               answer=(n*(n+1))/2;
12         System.out.println(answer);
13     }
14 
15 }
原文地址:https://www.cnblogs.com/Catherinezhilin/p/8482102.html