HDOJ 1097 A HARD PUZZLE

找规律的:

 1 #include <iostream>
 2 #include <cmath>
 3 
 4 using namespace std;
 5 
 6 int main()
 7 {
 8     int a,b;
 9     while(cin>>a>>b)
10     {
11       b=b%4;//最多就4种情况
12       a=a%10;
13       switch(b)
14       {
15       case 1:
16         cout<<a%10; break;
17       case 2:
18         cout<<a*a%10; break;
19       case 3:
20         cout<<a*a*a%10; break;
21       case 0:
22         cout<<a*a*a*a%10;
23       }
24 
25       cout<<endl;
26     }
27 
28     return 0;
29 }
原文地址:https://www.cnblogs.com/CKboss/p/3014140.html