【codeforces】CF11A Increasing Sequence (题解)

CF11A Increasing Sequence


入门题,就不解释了

题解:

算法复杂度为O(n)

#include <iostream>
#include <algorithm>
using namespace std;
int a[2001];
int main()
{
    int n,b,ans;
    cin>>n>>b;
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
    }
    for(int i=2;i<=n;i++)
    {
        if(a[i]<=a[i-1])
        {
            ans +=(a[i-1]-a[i])/b;
            a[i]=a[i]+((a[i-1]-a[i])/b+1)*b;
            ans++;
        }
    }
    cout<<ans<<endl;
}
原文地址:https://www.cnblogs.com/BorisDimitri/p/13546618.html