洛谷 P1201 [USACO1.1]贪婪的送礼者Greedy Gift Givers

贪婪的送礼者Greedy Gift Givers

难度:☆

Code:

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
using namespace std;
//Mystery_Sky
//
struct People{
    char name[20];
    int out, in;
}people[100];
int n;
char name[20], name1[20];
inline int search_name(char name[])
{
    int a;
    for(int j = 1; j <= n; j++) {
        if((strcmp(name, people[j].name) == 0)) {
                a = j;
                break;
        }
    }
    return a;
}

inline void solve()
{
    for(int i = 1; i <= n; i++) {
        scanf("%s", name);
        int a;
        a = search_name(name);
        int b, c;
        getchar();
        scanf("%d%d", &b, &c);
        if(c == 0) continue;
        int out = b / c;
        people[a].out = people[a].out + out * c;
        for(int j = 1; j <= c; j++) {
            scanf("%s", name1);
            getchar();
            int d = search_name(name1);
            people[d].in += out;
        }
    }
}

inline void print()
{
    for(int i = 1; i <= n; i++) {
        printf("%s ", people[i].name);
        printf("%d
", people[i].in - people[i].out);
    }
}

int main() {
    scanf("%d", &n);
    for(int i = 1; i <= n; i++) scanf("%s", people[i].name);
    getchar();
    solve();
    print();
    return 0;
}
唯愿,青春不辜负梦想,未来星辰闪耀
原文地址:https://www.cnblogs.com/Benjamin-cpp/p/10951561.html