POJ 3253 Fence Repair 贪心

每次合并选最短的两块木板,用优先队列优化。

//#pragma comment(linker, "/STACK:1024000000,1024000000")
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
#include<iostream>
#include<sstream>
#include<cmath>
#include<climits>
#include<string>
#include<map>
#include<queue>
#include<vector>
#include<stack>
#include<set>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
#define pb(a) push(a)
#define INF 0x1f1f1f1f
#define lson idx<<1,l,mid
#define rson idx<<1|1,mid+1,r
#define PI  3.1415926535898
template<class T> T min(const T& a,const T& b,const T& c) {
    return min(min(a,b),min(a,c));
}
template<class T> T max(const T& a,const T& b,const T& c) {
    return max(max(a,b),max(a,c));
}
void debug() {
#ifdef ONLINE_JUDGE
#else

    freopen("in.txt","r",stdin);
    //freopen("d:\out1.txt","w",stdout);
#endif
}
int getch() {
    int ch;
    while((ch=getchar())!=EOF) {
        if(ch!=' '&&ch!='
')return ch;
    }
    return EOF;
}

int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        priority_queue<int,vector<int>,greater<int> > q;
        for(int i=1;i<=n;i++)
        {
            int x;
            scanf("%d",&x);
            q.push(x);
        }
        long long res=0;
        for(int i=1;i<n;i++)
        {
            int a=q.top();q.pop();
            int b=q.top();q.pop();
            res=res+a+b;
            q.push(a+b);
        }
        printf("%I64d
",res);
    }
    return 0;
}
View Code
原文地址:https://www.cnblogs.com/BMan/p/3645347.html