关于裴蜀定理。

某谷模板 https://www.luogu.org/problemnew/show/P4549

百度词条 https://baike.baidu.com/item/%E8%A3%B4%E8%9C%80%E5%AE%9A%E7%90%86

推荐博客 http://www.cnblogs.com/aininot260/p/9477754.html

 1 #include<cstdio>
 2 #include<cmath>
 3 using namespace std;
 4 int gcd(int a,int b){return b==0?a:gcd(b,a%b);}
 5 int n, ans;
 6 int main(){
 7     scanf("%d",&n);
 8     int x;
 9     for(int i=1; i<=n; i++){
10         scanf("%d",&x);
11         ans=gcd(ans,x);
12     }
13     printf("%d",abs(ans));
14     return 0;
15 }