ACwing89 a^b 快速幂取模

网址:https://www.acwing.com/problem/content/91/

题解:

快速幂取模板子题。

AC代码:

#include <bits/stdc++.h>
using namespace std;
long long inv(long long a, long long b, long long p)
{
	long long res = 1;
	while (b)
	{
		if (b & 1)
			res = (res * a) % p;
		a = (a * a) % p;
		b >>= 1;
	}
	return res % p;
}
int main()
{
	long long a, b, p;
	scanf("%lld%lld%lld", &a, &b, &p);
	printf("%lld
", inv(a, b, p));
	return 0;
}

  

原文地址:https://www.cnblogs.com/Aya-Uchida/p/11470201.html