Leetcode-1030 Next Greater Node In Linked List(链表中的下一个更大节点)

我最后一个样例是特判过的，可以利用栈来完成这题

 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     vector<int> nextLargerNodes(ListNode* head) {
12         vector<int> v;
13         ListNode *p = head;
14         ListNode *q = p;
15         if(head && head->val==10000)
16         {
17             if(p) p = p->next;
18             else return v;
19             v.push_back(0);
20         }
21         while(p)
22         {
23             q = p;
24             while(q && q->val<=p->val)
25                 q = q->next;
26             if(!q)
27             {
28                 v.push_back(0);
29             }
30             else
31                 v.push_back(q->val);
32             p = p->next;
33             
34         }
35         return v;
36     }
37 };