[Javascirpt AST] Babel Plugin -- create new CallExpression

The code we want to trasform:

2 ** 3;
a ** b;
a **b * c;
a ** b ** c;
(a+1) ** (b+1);

transform to:

Math.pow(2, 3);
Math.pow(a, b);
Math.pow(a, b) * c;
Math.pow(a, Math.pow(b, c));
Math.pow(a+1, b+1);

Code:

export default function (babel) {
  const { types: t } = babel;
  
  return {
    name: "ast-transform", // not required
    visitor: {
      BinaryExpression (path) {
        console.log(t )
        const isPowOpreator = path.node.operator === '**';
        if(!isPowOpreator) {
           return;
        }
        
        const {left, right} = path.node;

        path.replaceWith(t.callExpression( // create Math.pow() node
          t.memberExpression(
            t.identifier('Math'),
            t.identifier('pow')
          ),
          [left, right]  // pass in Math.pow(left, right)
        ))
      }
    }
  };
}