[Immutable.js] Working with Subsets of an Immutable.js Map()

Immutable.js offers methods to break immutable structures into subsets much like Array--for instance it has the all powerful slice()--and unlike Array it offers functional methods like take() and skip(). You get the best of both the imperative and functional worlds.

mocha.setup('bdd');
const expect = chai.expect;

class Todo {
  
  constructor(title="", text="", completed=false) {
    this.id = (+new Date() + Math.floor(Math.random() * 999999)).toString(36);
    this.title = title;
    this.text = text;
    this.completed = completed;
  }
  
}

function addTodo(todos, todo) {
  return todos.set(todo.id, todo);
}

function retrieveFinalPair(todos) {
  return todos.slice(todos.size-2, todos.size);
  // Alernatively, you can use this terser syntax
  //return todos.slice(-2);
}

function removeLastEntry(todos) {
  return todos.slice(0, -1);
}

function removeFirstEntry(todos) {
  return todos.slice(1, todos.size);
}

function removeFirstFive(todos) {
  return todos.skip(5);
}

function findMeMonkey(todos) {
  return todos.skipUntil(todo => todo.text === "monkey" );
}

function stopAtMonkey(todos) {
  return todos.skipWhile(todo => todo.text === "monkey" );
}

describe('Working with Subsets of an Immutable.js Map()', () => {
  
  it('should retrieve last two entries using slice()', () => {

    var todos = Immutable.Map();
    
    _.each(_.range(10), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, "I'm a todo!", false));
    });

    const lastTwoTodos = retrieveFinalPair(todos);
    
    expect(lastTwoTodos.size).to.equal(2);
    
    todos.takeLast(2).forEach(todo => {
      expect(lastTwoTodos.get(todo.id)).to.equal(todo);
    });
    
  });
  
  it('should remove last entry using negative slice()', () => {

    var todos = Immutable.Map();
    
    _.each(_.range(10), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, "I'm a todo!", false));
    });

    const todosWithoutLast = removeLastEntry(todos);
    
    todos.butLast().forEach(todo => {
      expect(todosWithoutLast.get(todo.id)).to.equal(todo);
    });
    
  });
  
  it('should remove first entry using slice()', () => {

    var todos = Immutable.Map();
    
    _.each(_.range(10), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, "I'm a todo!", false));
    });

    const todosWithoutFirst = removeFirstEntry(todos);
    
    todos.rest().forEach(todo => {
      expect(todosWithoutFirst.get(todo.id)).to.equal(todo);
    });
    
  });
  
  it('should return last 5 todos using skip()', () => {

    var todos = Immutable.Map();
    
    _.each(_.range(10), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, "I'm a todo!", false));
    });

    const lastFive = removeFirstFive(todos);
    
    todos.takeLast(5).forEach(todo => {
      expect(lastFive.get(todo.id)).to.equal(todo);
    });
    
  });  
  
  it('should return todos after reaching "monkey" using skipUntil()', () => {

    var texts = ["dog", "cat", "frog", "monkey", "octopus", "horse", "orangutan"];
    var todos = Immutable.Map();
    
    _.each(_.range(texts.length), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, texts[index], false));
    });

    const monkeyAndAfter = findMeMonkey(todos);
    
    todos.takeLast(4).forEach(todo => {
      expect(monkeyAndAfter.get(todo.id)).to.equal(todo);
    });
    
  });  
  
  it('should return todos up to reaching "monkey" using skipWhile()', () => {

    var texts = ["dog", "cat", "frog", "monkey", "octopus", "horse", "orangutan"];
    var todos = Immutable.Map();
    
    _.each(_.range(texts.length), (index) => {
      todos = addTodo(todos, new Todo("Todo" + index, texts[index], false));
    });

    const upToMonkey = stopAtMonkey(todos);
    
    todos.take(4).forEach(todo => {
      expect(upToMonkey.get(todo.id)).to.equal(todo);
    });
    
  });
  
});

mocha.run();
原文地址:https://www.cnblogs.com/Answer1215/p/5229557.html