信号量解决同步问题

// 06 信号量解决线程同步问题.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include <windows.h>
int g_n;
HANDLE  hSemaphore;
DWORD WINAPI ThreadPro1(LPVOID lpThreadParameter){
    for (int i = 0; i < 10000000; i++)
    {
        WaitForSingleObject(hSemaphore, -1);
        g_n++;
        printf("我在线程1:%d
", g_n);
        Sleep(100);
        ReleaseSemaphore(hSemaphore,1,NULL);
    }
    return 0;
}
DWORD WINAPI ThreadPro2(LPVOID lpThreadParameter){
    for (int i = 0; i < 10000000; i++)
    {
        WaitForSingleObject(hSemaphore, -1);
        g_n++;
        printf("我在线程2:%d
", g_n);
        Sleep(100);
        ReleaseSemaphore(hSemaphore,1, NULL);
    }
    return 0;
}
int _tmain(int argc, _TCHAR* argv[]){

    HANDLE hThread1 = 0, hThread2;
    //创建一个创建一个锁孔的信号量
    hSemaphore = CreateSemaphore(NULL,1,1,NULL);
    hThread1 = CreateThread(NULL, NULL, ThreadPro1, NULL, NULL, NULL);
    hThread2 = CreateThread(NULL, NULL, ThreadPro2, NULL, NULL, NULL);
    WaitForSingleObject(hThread1, -1);
    WaitForSingleObject(hThread2, -1);
    printf("%d", g_n);
    return 0;
}
原文地址:https://www.cnblogs.com/Alyoyojie/p/5317296.html