现代密码学

ll pow_mod(ll a,ll b) {
    ll res = 1;
    while (b) {
        if (b & 1) res = res * a % mod;
        a = a * a % mod;
        b >>= 1;
    }
    return res;
}
原文地址:https://www.cnblogs.com/Accpted/p/12626870.html