最小生成树计数

最小生成树计数

#include <bits/stdc++.h>

using namespace std;
const int maxn=1010;
const int mod=31011;
struct edge{
    int u,v,w;
    bool operator<(const edge & b)const {
        return w<b.w;
    }
}a[maxn];

struct node{
    int l,r,num;
}b[maxn];
int  n,m,fa[maxn],num,tot,ans=1,sum;
int fin(int x) {
    if (x == fa[x])
        return x;
    return fin(fa[x]);
}

void dfs(int i,int now,int k){
    if (now==b[i].r+1){
        if (k==b[i].num) sum++;
        return;
    }
    int u=fin(a[now].u),v=fin(a[now].v);
    if (u!=v){
        fa[u]=v;
        dfs(i,now+1,k+1);
        fa[u]=u;fa[v]=v;
    }
    dfs(i,now+1,k);
}
int main() {
    scanf("%d%d", &n, &m);
    for (int i = 1; i <= n; i++) fa[i] = i;
    for (int i = 1; i <= m; i++) {
        scanf("%d%d%d", &a[i].u, &a[i].v, &a[i].w);
    }
    sort(a + 1, a + m + 1);
    for (int i = 1; i <= m; i++) {
        if (a[i].w != a[i - 1].w) {
            b[++num].l = i;
            b[num - 1].r = i - 1;
        }
        int u = fin(a[i].u), v = fin(a[i].v);
        if (u != v) {
            fa[u] = v;
            tot++;
            b[num].num++;
        }
    }
    b[num].r = m;
    if (tot != n - 1) {
        printf("0
");
        return 0;
    }
    for (int i = 1; i <= n; i++) fa[i] = i;
    for (int i = 1; i <= num; i++) {
        sum = 0;
        dfs(i, b[i].l, 0);
        ans = ans * sum % mod;
        for (int j = b[i].l; j <= b[i].r; j++) {
            int u = fin(a[j].u), v = fin(a[j].v);
            if (u != v) fa[u] = v;
        }
    }
    printf("%d
", ans);
    return 0;
}

  

原文地址:https://www.cnblogs.com/Accpted/p/11433240.html