php+jquery+ajax+json的一个最简单实例

    function ajaxTest(){
    $username = $_POST['username'];
$age = $_POST['age'];
$job = $_POST['job'];
$json_arr = array("username"=>$username,"age"=>$age,"job"=>$job);
$json_obj = json_encode($json_arr);
echo $json_obj;
        }

<html>
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<script type="text/javascript" src="/Js/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
$("#send").click(function(){
   var cont = $("input").serialize();
   $.ajax({
    url:"{:url('/index/index/ajaxTest')}",
    type:'post',
    dataType:'json',
    data:cont,
    success:function(data){
     var str = data.username + data.age + data.job;
     $("#result").html(str);
    }
   });
});
});
</script>
</head>
<body>
<div id="result">一会看显示结果</div>
<form id="my" action="" method="post">
<p><span>姓名：</span><input type="text" name="username" /></p>
<p><span>年龄：</span><input type="text" name="age" /></p>
<p><span>工作：</span><input type="text" name="job" /></p>
</form>
<button id="send">提交</button>
</body>
</html>