获得一个网址

import requests
def getHTMLText(url):
    try:
        r=requests.get(url,timeout=30)
        r.raise_for_status()
        r.encoding='utf-8'
        return r.text
    except:
        return ""
url="https://123.sogou.com"
print(getHTMLText(url))

  

原文地址:https://www.cnblogs.com/670ling/p/12898966.html