第十五节课:习题讲解

'''作业一:
请实现一个程序,实现如下需求点:
1.程序开始的时候提示用户输入学生年龄信息 格式如下:
Jack Green , 21 ; Mike Mos, 9;
我们假设 用户输入 上面的信息,必定会遵守下面的规则:
学生信息之间用分号隔开(分号前后可能有不定数量的空格),
每个学生信息里的 姓名和 年龄之间用 逗号隔开(逗号前后可能有不定数量的空格)

2. 程序随后将输入的学生信息分行显示,格式如下
Jack Green : 21;
Mike Mos : 09;
学生的姓名要求左对齐,宽度为20, 年龄信息右对齐,宽度为2位,不足前面补零123

思路分解:
1- 提示学生输入信息
2- 提取输入的信息中的两个要素
3- 将提取的信息进行字符串格式化

'''
# 1- 提示学生输入信息: input
# instr=input('请输如学生信息:')
# # print(instr) #打印得:Jack Green , 21 ; Mike Mos, 9;
# # 2- 提取输入的信息中的两个要素:name和age: split()
# info=instr.split(';') #以分号为分割符分割字符串,返回的列表
# del info[-1]
# # print(info) #打印得:['Jack Green , 21 ', ' Mike Mos, 9', '']
# for one in info:
# # print(one) #one就是info这个列表的每一个元素了,one是字符串,可以split
# temp=one.split(',') #以逗号为界限分割遍历到的one,返回的是列表
# # print(temp) #打印得:['Jack Green ', ' 21 '] [' Mike Mos', ' 9']
# name=temp[0].strip()
# age=temp[1].strip()
# # print(name) #打印得: Jack Green,Mike Mos,
# # print(age) #打印得:21 9,现在我们要拿到的两个元素都拿到了,可以格式化了
# print(f'{name:<20}: {age:>2}')

'''
作业二:
1.下面的log变量记录了云服务器上 当天上传的文件信息
其中第一列是文件名,第二列是文件大小

请编写一个程序,统计出不同类型的 文件的大小总和
比如:
jpeg 9988999
json 324324
png 2423233
----------------------------------


log = ''
f20180111014341/i_51a7hC3W.jpeg 169472 FrITJxleSP7wUD-MWw-phL_KP6Eu 15156063244230469 image/jpeg 0
f20180111014341/j_R0Hpl4EG.json 1036 ForGzwzV3e-uR3_UzvppJs1VgfQG 15156064773253144 application/json 0
f20180111020739/i_0TDKs0rD.jpeg 169472 FrITJxleSP7wUD-MWw-phL_KP6Eu 15156076847077556 image/jpeg 0
f20180111020739/j_JFO6xiir.json 1040 FmUhTchdLOd7LBoE8OXzPLDKcW60 15156077904192983 application/json 0
f20180111090619/i_1BwNksbL.jpg 49634 FtXBGmipcDha-67WQgGQR5shEBu2 15156329458714950 image/jpeg 0
f20180111090619/i_3BKlsRaZ.jpg 30152 FoWfMSuqz4TEQl5FT-FY5wqu5NGf 15156330575626044 image/jpeg 0
f20180111090619/i_5XboXSKh.jpg 40238 Fl84WaBWThHovIBsQaNFoIaPZcWh 15156329453409855 image/jpeg 0
f20180111090619/i_6DiYSBKp.jpg 74017 FrYG3icChRmFGnWQK6rYxa88KuQI 15156329461803290 image/jpeg 0
f20180111090619/i_76zaF2IM.jpg 38437 Fui8g5OrJh0GQqZzT9wtepfq99lJ 15156334738356648 image/jpeg 0
f20180111090619/i_B6TFYjks.jpg 37953 FleWqlK2W1ZmEgAatAEcm1gpR0kC 15156329464034474 image/jpeg 0
f20180111090619/i_N9eITqj3.jpg 38437 Fui8g5OrJh0GQqZzT9wtepfq99lJ 15156330419595764 image/jpeg 0
f20180111090619/i_QTSNWmA6.jpg 37953 FleWqlK2W1ZmEgAatAEcm1gpR0kC 15156333104224056 image/jpeg 0
f20180111090619/i_XdHcAfh1.jpg 56479 FjLQIQ3GxSEHDfu6tRcMylK1MZ05 15156334227270309 image/jpeg 0
f20180111090619/i_Xyy723MU.jpg 50076 FsfZpQzqu084RUw5NPYW9-Yfam_R 15156334229987458 image/jpeg 0
f20180111090619/i_d8Go0EOv.jpg 30152 FoWfMSuqz4TEQl5FT-FY5wqu5NGf 15156334736228515 image/jpeg 0
f20180111090619/i_diuHmX53.jpg 40591 FuTx1pw4idbKnV5MSvNGxCA5L470 15156333878320713 image/jpeg 0
f20180111090619/i_qQKzheSH.jpg 55858 Fj0A3i8V7fzzOiPQFL79ao15hkN9 15156329456666591 image/jpeg 0
f20180111090619/i_rHL5SYk8.jpg 40238 Fl84WaBWThHovIBsQaNFoIaPZcWh 15156336509742181 image/jpeg 0
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f20180111090619/j_4mxbEiVh.json 2990 Fpq-3yl3Yr1CadNrJVSDnpeRhQtT 15156331445226898 application/json 0
f20180111090619/j_i1K74768.json 3042 Fl5PpDw1TsZXMuhoq1RUrOeGZ6br 15156335067090003 application/json 0
f20180111095839/i_Q7KMKeda.png 518522 Fl-yB1_ruL2uxZN9k7DjB62h9dYH 15156359599713253 image/png 0
f20180111095839/j_5DpqHolV.json 184 FoYvi7cmSrzuVjUgCRzW5kU95SVo 15156359719719064 application/json 0
f20180111100442/i_No8kToIV.jpg 48975 Fu1cw3f--5Vpz9kLGeJfvljhCtyZ 15156364349642377 image/jpeg 0
f20180111100442/i_P1bkvSeg.jpg 68200 FvYe8vi46TjUKhEy_UwDqLhO6ZsW 15156363800690634 image/jpeg 0
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f20180111100442/i_X8d8BN07.jpg 50770 FivwidMiHbogw77lqgkIKrgmF3eA 15156363969737156 image/jpeg 0
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f20180111100442/i_xrOT98on.jpg 50021 Fql7ookM1Rc6V7VairKAfnKe-o9w 15156363856357316 image/jpeg 0
f20180111135114/i_Zqt8Tmoe.png 161629 FlELw59_mV3VqDBLyu1BKN4fIWnx 15156500155209863 image/png 0
f20180111135114/j_uhHoMXKq.json 159 FrypljwAr2LgoLAePBNTUYTUAgDt 15156500200488238 application/json 0
f20180111142119/i_s83iZ2GR.png 92278 Fns8tdh3JCkRmfE_COYEu4o8w03E 15156517082371259 image/png 0
f20180111142119/j_0g45JRth.json 159 Fq1rFwdRguYRXrp61nGZ5TsUG1V- 15156517143375596 application/json 0
f20180111144306/i_yE5TC84E.png 139230 Fjf61ymabEnEvnr5ZMHFjXGCrYlP 15156530038824150 image/png 0
f20180111144306/j_OF4WVtSH.json 159 FqwkKcxfo8jd0jFUyuH4X2CrnE9q 15156530083419530 application/json 0
f20180111150230/i_KtnER4g3.png 120044 FuwOWdrqzcr2-UScem-LzEMgMezs 15156541734892258 image/png 0
f20180111150230/j_xMSUEejY.json 158 FjJr_4deMqFphGaptm-2Pa6wwRP2 15156541771989216 application/json 0
f20180111151741/i_JuSWztB3.jpg 92506 FrIjRevHSi6xv4-NQa2wrHu5a1zQ 15156550875370965 image/jpeg 0
f20180111153550/i_9wWzVenl.gif 769872 FvslKY9JUaCQm-lu02E34tvAP_oG 15156561674621628 image/gif 0
''
思路分解:
1- 获取每一行的文件类型与大小
2- 对文件类型相同的文件大小做统计
思路:空列表拿一个空盒子和文件类型大小合集比,如果该类型不在结果列表中,新增一个组合

'''
log = '''
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f20180111014341/j_R0Hpl4EG.json 1036 ForGzwzV3e-uR3_UzvppJs1VgfQG 15156064773253144 application/json 0
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f20180111090619/i_6DiYSBKp.jpg 74017 FrYG3icChRmFGnWQK6rYxa88KuQI 15156329461803290 image/jpeg 0
f20180111090619/i_76zaF2IM.jpg 38437 Fui8g5OrJh0GQqZzT9wtepfq99lJ 15156334738356648 image/jpeg 0
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'''
# 两种方法做这题,一:标记法:
# reslist=[] #现在定义一个空列表,用于后续存放文件类型和大小[[类型一,大小一],[类型二,大小二]]
# # 1- 获取每一行数据的文件类型与大小
# # log变量中,每一行都有换行符,姑且先用换行符分割
# lines=log.split(' ') #lines返回的是列表,但是里面的元素是字符串,是每一行的内容
# # print(lines)
# del lines[0],lines[-1] #删除头尾的空字符串
# # 现在要操作每一盒元素,用for循环来操作遍历
# for one in lines: #先取出每个元素,再对每一行的元素进行切割
# line=one.split(' ')
# # print(line)
# filetype=line[0].split('.')[-1].strip() #直接获取到文件名之后再以.进行切割,-1位就是需要的文件类型
# filesize=int(line[1].strip()) #因为后续要累加,所以得转化为int型
# # print(filetype,filesize) #到现在为止,第一步目标完成
# # 2- 统计同类型文件的size总和 先讲方法一:
# inflag=False #定义标记初始值,因为当为TRUE的时候训练内部要去遍历每一行的数据
# # 那么,怎么判断类型在不在结果列表呢?比较对象永远是reslist列表的字列表中的第一个元素
# for one in reslist:
# reas=one[0]
# if reas==filetype: #如果每一个0下标等于filetype,说明文件都在这个reslist表里了
# # 在,如果该类型在结果列表中,累加到这个字列表的第二个元素中去
# one[1]+=filesize
# # 如果整个for循环遍历完one[0]都不等于filetype,说明reslist里面还没有这个filetype,此时新增一个组合
# inflag=True #做一个标记,
# break #优化性能,即如果一旦reslist表里找到有这个filetype,累加成功之后就可以直接跳出循环,用下一个空盒子去跟filetype作比较
# if inflag==False: #这个意思是,如果reslist里面还没有这个filetype,此时新增一个组合
# reslist.append([filetype,filesize])
# print(reslist)

# 二:字典存储法:
# resdict={} #{'类型1':大小1}
# lines=log.split(' ')
# del lines[0],lines[-1]
# # print(lines)
# for line in lines:
# temp=line.split(' ')
# # print(temp)
# filename=temp[0].split('.')[-1]
# filesize=int(temp[1].strip()) #因为后面要累加,所以这里要强制转换成int类型
# # print(filename,filesize)
# # 如果该类型不在字典里,就新增键值对
# if filename not in resdict:
# resdict[filename]=filesize
# # 思路:如果类型在字典里,就在这个类型的后面累加大小
# else:
# resdict[filename]+=filesize
# print(resdict) #注释掉之前的print,打印得:{'jpeg': 412560, 'json': 8927, 'jpg': 1374206, 'png': 1031703, 'gif': 769872}




















原文地址:https://www.cnblogs.com/66-liu/p/13869836.html