JSONArray排序[收藏]

问题

JSONArray中嵌套JSONObject, 对JSONArray进行排序

排序前:

[{"id":1,"name":"ljw"},{"id":3,"name":"ljw"},{"id":2,"name":"ljw"}]

排序后:

[{"id":1,"name":"ljw"},{"id":2,"name":"ljw"},{"id":3,"name":"ljw"}]

利用Collections.sort()

JSONObject o1 = JSONObject.parseObject("{"id":1,"name":"ljw"}");
JSONObject o2 = JSONObject.parseObject("{"id":3,"name":"ljw"}");
JSONObject o3 = JSONObject.parseObject("{"id":2,"name":"ljw"}");
JSONArray a = new JSONArray();
a.add(o1);
a.add(o2);
a.add(o3);
//转list 1
List<JSONObject> list = JSONArray.parseArray(a.toJSONString(), JSONObject.class);
//转list 2
//List<JSONObject> list = new ArrayList<JSONObject>();
//for (int i = 0; i < a.size(); i++) {
//    list.add((JSONObject) a.get(i));
//}
System.out.println("排序前:"+a);
Collections.sort(list, new Comparator<JSONObject>() {
    @Override
    public int compare(JSONObject o1, JSONObject o2) {
        int a = o1.getInteger("id");
        int b = o2.getInteger("id");
        if (a > b) {
            return 1;
        } else if(a == b) {
            return 0;
        } else
            return -1;
        }
});
JSONArray jsonArray = JSONArray.parseArray(list.toString());
System.out.println("排序后:" + jsonArray);

原文地址

原文地址:https://www.cnblogs.com/52liming/p/9585374.html