ORACLE 中的 ROW_NUMBER() OVER() 分析函数的用法

 
以下 转载自:https://www.cnblogs.com/iliuyuet/p/4585666.html
语法:ROW_NUMBER() OVER(ORDER BY COLUMN)

  简单的说row_number()从1开始,为每一条分组记录返回一个数字,这里的SELECT ACD_ID,ROW_NUMBER() OVER(ORDER BY ACD_ID DESC) FROM CC_ACDINFO;是先把ACD_ID列降序,再为降序以后的每条ACD_ID记录返回一个序号。

SELECT ACD_ID,ROW_NUMBER() OVER(ORDER BY ACD_ID DESC) FROM CC_ACDINFO;
---------------------------------------------------------   "ACD_ID" "ROW_NUMBER()
OVER(ORDERBYACD_ID" "174" "1" "154" "2" "114" "3" "75" "4"
 
ORACLE 中的 ROW_NUMBER() OVER() --分析函数的用法

ROW_NUMBER() OVER(partition by col1 order by col2) --表示根据col1分组,在分组内部根据col2排序,而此函数计算的值就表示每组内部排序后的顺序编号(组内是连续且唯一的)。

举例:

SQL> DESC T1;

Name                                           Null?    Type
----------------------------------------- -------- ----------------------------
ID                                                    NUMBER
NAME                                                    VARCHAR2(10)
DATE1                                                    DATE

SQL> SELECT * FROM T1;
        ID NAME                           DATE1
---------- ------------------------------ ------------------
       101 aaa                                  09-SEP-13

       101 bbb                                  10-SEP-13

       101 ccc                                  11-SEP-13

       102 ddd                                  08-SEP-13

       102 eee                                  11-SEP-13

 

SQL> SELECT ID,NAME,DATE1,ROW_NUMBER() OVER(partition by ID order by DATE1 desc) as RN FROM T1;

    ID NAME               DATE1               RN
---------- ------------------------------ ------------------ ----------
       101 ccc                  11-SEP-13              1
       101 bbb                  10-SEP-13              2
       101 aaa                  09-SEP-13              3
       102 eee                  11-SEP-13              1
       102 ddd                  08-SEP-13              2

把上面语句作为一个子表语句,嵌入到另一条语句中:

 SQL> SELECT ID,NAME,DATE1 FROM (SELECT ID,NAME,DATE1,ROW_NUMBER() OVER(partition by ID order by DATE1 desc) as RN FROM T1)T WHERE T.RN=1;

        ID NAME                           DATE1
---------- ------------------------------ ------------------
       101 ccc                                  11-SEP-13
       102 eee                                  11-SEP-13
原文地址:https://www.cnblogs.com/520future/p/8288662.html