mysql没有partition by关键字,怎么实现分组取第一行数据?用MySQL的SUBSTRING_INDEX解决!

Oracle中的SQL如下(改造前):
select username,PARTITION BY age order by age desc uuid
from 

( select uuid ,username ,`password` ,age from `user` ) b

GROUP BY uuid asc;

(网上copy的代码,有误,但我们关注的重点是关键字改造替换后的区别!)

MySQL中的SQL如下(改造后):
select username,SUBSTRING_INDEX( GROUP_CONCAT(age order by age desc) ,',',1) uuid 
from 
(
select uuid
,username
,`password`
,age
from `user`
)b 
GROUP BY uuid asc;

原文地址:https://www.cnblogs.com/4AMLJW/p/SUBSTRING_INDEX202003171132.html