P4213 【模板】杜教筛(Sum)

思路:杜教筛模板题。

#include <algorithm>
#include <cstdio>
#include <cstring>
#include <map>
using namespace std;
const int maxn = 2000010;
typedef long long ll;
ll T, n, pri[maxn], cur, mu[maxn], sum_mu[maxn];
bool vis[maxn];
map<ll, ll> mp_mu;
ll S_mu(ll x) {
  if (x < maxn) return sum_mu[x];
  if (mp_mu[x]) return mp_mu[x];
  ll ret = 1ll;
  for (ll i = 2, j; i <= x; i = j + 1) {
    j = x / (x / i);
    ret -= S_mu(x / i) * (j - i + 1);
  }
  return mp_mu[x] = ret;
}
ll S_phi(ll x) {
  ll ret = 0ll;
  for (ll i = 1, j; i <= x; i = j + 1) {
    j = x / (x / i);
    ret += (S_mu(j) - S_mu(i - 1)) * (x / i) * (x / i);
  }
  return ((ret - 1) >> 1) + 1;
}
int main() {
  scanf("%lld", &T);
  mu[1] = 1;
  for (int i = 2; i < maxn; i++) {
    if (!vis[i]) {
      pri[++cur] = i;
      mu[i] = -1;
    }
    for (int j = 1; j <= cur && i * pri[j] < maxn; j++) {
      vis[i * pri[j]] = true;
      if (i % pri[j])
        mu[i * pri[j]] = -mu[i];
      else {
        mu[i * pri[j]] = 0;
        break;
      }
    }
  }
  for (int i = 1; i < maxn; i++) sum_mu[i] = sum_mu[i - 1] + mu[i];
  while (T--) {
    scanf("%lld", &n);
    printf("%lld %lld
", S_phi(n), S_mu(n));
  }
  return 0;
}
原文地址:https://www.cnblogs.com/2462478392Lee/p/13774273.html