ppt 例题8 多重背包

#include <stdio.h>
#include <string.h>
int dp[60001];
void f(int maxv,int n,int c[ ],int v[ ])
                                              //最大可能价值、 物品种类、物品数量、物品价值
{   int i,j,k,t;
    memset(dp,0,sizeof(dp));
    dp[0] = 1;
    for ( i = 1; i <=n; i++) //物品种类                                                           // 物品种类  从1开始
        for (j = maxv; j>=0; j--)   //必须从背包容量向下循环                                               //j 从最大的 开始
            if (dp[j])
            {   t = j;                                                                      //  t 的 初值为 j
                for ( k = 1; k <= c[i]; k++)    //物品数量循环
                     dp[t=t+v[i]] = 1;                                                                             // t 也会变化
            }
}

int main()
{   int i,sum;
    int c[7],v[7];  //物品的数量与价值
    while (1)
    {   sum = 0;
        for (i = 1; i <= 6; i++) //输入6种物品的个数
        {   scanf("%d",&c[i]);   v[i]=i;  sum += c[i]*v[i];  }
        if (sum==0)  break;
        if (sum%2)  { printf("Can't ");   continue;  }
        f(sum,6,c,v);     //调用模版函数f()
        if (dp[sum/2]==1) printf("Can ");
        else printf("Can't ");
    }
    return 0;
}