作业二 分支循环结构

#include<stdio.h>
int main(void)
{
    int i,n;
    double x,sum;
    printf("Enter x,n:");
    scanf("%lf%d",&x,&n);
    sum=1;
    for(i=1;i<=n;i++){
    sum=sum*x;
    }
    printf("x^n=%.2f
",sum);
    return 0;
}
#include<stdio.h>
int main(void)
{
    double num1,num2;
    char op;

    printf("Type in an expression:");
    scanf("%lf%c%lf",&num1,&op,&num2);

    if(op=='+')
        printf("=%.2f
",num1+num2);
    else if(op=='-')
        printf("=%.2f
",num1-num2);
    else if(op=='*')
        printf("=%.2f
",num1*num2);
    else if(op=='/')
        printf("=%.2f
",num1/num2);
    else
        printf("Unknown operator
");

    return 0;

}
原文地址:https://www.cnblogs.com/2013djj/p/3379089.html