例3-11

#include<stdio.h> int main(void) {  double valuel,value2;  char op;

 printf("Type in an expression:");  scanf("%lf%c%lf",&valuel,&op,&value2);  if(op=='+')   printf("=%.2f ",valuel,&op,&value2);  else if(op=='-')   printf("=%.2f ",valuel-value2);  else if(op=='*')   printf("=%.2f ",valuel*value2);  else if(op=='/')   if(value2!=0)    printf("=%.2f ",valuel/value2);   else    printf("Divisor can not be 0! ");  else   printf("Unknown operator! ");  return 0; }

原文地址:https://www.cnblogs.com/2013djj/p/3353864.html