c语言程序 第二例

求5！

# include <studio.h>

int main(){

int i,t;

t=1;

i=2;

while (i<=5){

t=t*i

i=i+1

}

printf("%d ",t);

return 0;

}

求1-1/2+1/3-1/4+........+1/99-1/100的值

#include <studio.h>

int main(){

int sign=1;

double  deno=2.0,sum=1.0,term;

while(deno<=100){

sign=-sign;

term=sign/deno;

sum=sum+term;

deno=deno+1;

}

printf("%f ",sum);

return 0;

}

枚举类型：enum

空类型：void