作业2

1.1字符切割

#include<stdio.h>
int judge_char(char *c);
int judge_black(char *c);
int judge_3(char *c);
int main(void) {
	char s[100];
	int i = 0, count = 0;
	gets_s(s);
	while (s[i] != '') {
		if (judge_char(&s[i])==1) {
			count++;
			i++;
			continue;
		}

		if (judge_black(&s[i])==1) {
			while (s[i] == ' ') {
				i++;
				if (s[i] == '') {
					break;
				}
			}
			continue;
		}

		if (judge_3(&s[i]) == 1) {
			while (judge_3(&s[i]) == 1) {
				i++;
				if (s[i] == '') {
					break;
				}
			}
			count++;
			continue;
		}

	}
	printf("%d", count);
	return 0;
} 
int judge_char(char* c) {//判断是否为标点符号
	if (*c != ' ' && ((*c >= '0' && *c <= '9') || (*c >= 'a' && *c <= 'z') || (*c >= 'A' && *c <= 'Z')) == 0) {
		return 1;
}
	return 0;
}
int judge_black(char* c) {//判断是否为空格
	if (*c == ' ') {
		return 1;
	}
	return 0;
}
int judge_3(char* c) { //判断是否为字母或者数字
	if ((*c >= '0' && *c <= '9') || (*c >= 'a' && *c <= 'z') || (*c >= 'A' && *c <= 'Z')) {
		return 1;
	}
	return 0;
}

1.2字符输出

#include<stdio.h>
int judge_char(char *c);
int judge_black(char *c);
int judge_3(char *c);
int main(void) {
	char s[100];
	int i = 0, count = 0;
	gets_s(s);
	while (s[i] != '') {
		if (judge_char(&s[i])==1) {
			char *p = &s[i];
			printf("%c
",*p);
			count++;
			i++;
			continue;
		}

		if (judge_black(&s[i])==1) {
			while (s[i] == ' ') {
				i++;
				if (s[i] == '') {
					break;
				}
			}
			continue;
		}

		if (judge_3(&s[i]) == 1) {
			while (judge_3(&s[i]) == 1) {
				char* p = &s[i];
				printf("%c",*p);
				i++;
				if (s[i] == '') {
					break;
				}
			}
			printf("
");
			count++;
			continue;
		}

	}
	printf("%d", count);
	return 0;
} 
int judge_char(char* c) {//判断是否为标点符号
	if (*c != ' ' && ((*c >= '0' && *c <= '9') || (*c >= 'a' && *c <= 'z') || (*c >= 'A' && *c <= 'Z')) == 0) {
		return 1;
}
	return 0;
}
int judge_black(char* c) {//判断是否为空格
	if (*c == ' ') {
		return 1;
	}
	return 0;
}
int judge_3(char* c) { //判断是否为字母或者数字
	if ((*c >= '0' && *c <= '9') || (*c >= 'a' && *c <= 'z') || (*c >= 'A' && *c <= 'Z')) {
		return 1;
	}
	return 0;
}

1.4变长数组

#include <stdio.h>
#include <stdlib.h>

int* MyArray();
int main()
{
	int* myArray = MyArray();//myArray接受动态创建的数组返回的地址
	//printf("%d ", myArray[0]);
	//printf("%d ", myArray[1]);
	//printf("%d ", myArray[2]);检测用
	return 0;
}
int* MyArray() { //当输入为9999时结束
	int* p = NULL, * q = NULL, x, count = 0;//p为传输 q为记录
	scanf_s("%d", &x);
	while (x != 9999) {
		count++;
		if (count == 1) {
			p = (int*)malloc(sizeof(int));
			p[count - 1] = x;
		}
		else {
			q = (int*)malloc((count - 1) * sizeof(int));
			q = p;
			p = (int*)malloc(count * sizeof(int));
			p = q;
			p[count - 1] = x;
		}
		scanf_s("%d", &x);
	}
	return q;
}

2.1神仙吧!!!(我是废物呜呜)

#include<iostream>
#include<stdlib.h>
#include<sstream>
#include<string.h>
#include<string>
#define FILE_BUFFER_LENGTH 30000
using namespace std;
void cheng(string s1, string s2) {
	int length_1 = s1.length(); //字符串1的长度
	int length_2 = s2.length(); //字符串2的长度
	int sum_len = length_1 + length_2;//字符串的总长 两数字相乘最大的位数为 数字1的位数+数字2的位数
	int max_len, min_len; //较大的字符串长度 和 较小的字符串长度
	string max_num, min_num; //通过字符串长度比较原数字大小
	if (length_1 > length_2) { //比较大小
		max_num = s1;
		min_num = s2;
		max_len = length_1;
		min_len = length_2;
	}
	else {
		max_num = s2;
		min_num = s1;
		max_len = length_2;
		min_len = length_1;
	}
	int* tmp_num = new int[sum_len]; //记录 较小数字的某一位数 与 较大数字的每一位数字 的积
	int* sum_num = new int[sum_len];  //相乘后最终的结果

	for (int i = 0; i < sum_len; i++) { //申请的数组清零
		sum_num[i] = 0;
		tmp_num[i] = 0;
	}
	int mulJin = 0, addJin = 0;                     //mulJin 为代替进位
	for (int i = min_len - 1; i >= 0; i--) {
		int k = --sum_len;
		for (int j = max_len - 1; j >= 0; j--) {
			tmp_num[k] = ((max_num[j] - '0') * (min_num[i] - '0') + mulJin) % 10;  //
			mulJin = ((max_num[j] - '0') * (min_num[i] - '0') + mulJin) / 10;
			k--;
		}
		if (mulJin > 0) {
			tmp_num[k] = mulJin;
		}
		mulJin = 0;
		for (int i = length_1 + length_2 - 1; i >= 0; i--) {
			int tmp = (sum_num[i] + tmp_num[i] + addJin);  // 代替同一位上的数字相加的和
			sum_num[i] = tmp % 10;                         // 超过10进位
			addJin = tmp / 10;                             // 进多少位
		}
		addJin = 0;
	}
	for (int i = 0; i < length_1 + length_2; i++) {   //代替用的数组清零
		tmp_num[i] = 0;
	}
	int t = 0;
	while (true) {                 //剔除前导0
		if (sum_num[t] == 0) {
			t++;
		}
		else {
			break;
		}
	}
	for (; t < length_1 + length_2; t++) {
		cout << sum_num[t];
	}
}
int zhuanghua(string s) { //将所得到的地址转化为字符串后 动态分配内存生存一个数组 十六进制转化十进制后返回数字
	int* p = NULL;
	int i = sizeof(s);//字符串长度;
	int len = 0;
	int index = 0;
	int sum = 0; //转化进制后的数字
	p = (int*)malloc(i * sizeof(int));
	if (p == NULL) {
		printf("内存分配失败
");
	}
	else {
		while (s[len] != '') {
			switch (s[len])
			{
			case '0':
				p[len++] = 0;
				break;
			case '1':
				p[len++] = 1;
				break;
			case '2':
				p[len++] = 2;
				break;
			case '3':
				p[len++] = 3;
				break;
			case '4':
				p[len++] = 4;
				break;
			case '5':
				p[len++] = 5;
				break;
			case '6':
				p[len++] = 6;
				break;
			case '7':
				p[len++] = 7;
				break;
			case '8':
				p[len++] = 8;
				break;
			case '9':
				p[len++] = 9;
				break;
			case 'A':
				p[len++] = 10;
				break;
			case 'B':
				p[len++] = 11;
				break;
			case 'C':
				p[len++] = 12;
				break;
			case 'D':
				p[len++] = 13;
				break;
			case 'E':
				p[len++] = 14;
				break;
			case 'F':
				p[len++] = 15;
				break;
			case 'a':
				p[len++] = 10;
				break;
			case 'b':
				p[len++] = 11;
				break;
			case 'c':
				p[len++] = 12;
				break;
			case 'd':
				p[len++] = 13;
				break;
			case 'e':
				p[len++] = 14;
				break;
			case 'f':
				p[len++] = 15;
				break;
			}
		}
	}
	index = len;
	for (i = 0; i < len; i++)
	{
		sum += p[i] * pow(16, index - 1);
		index--;
	}
	return sum;
}
int main(void)
{
	int x;
	cin >> x;
	int* p=&x;      //定义一个int类型的变量 给予任意数值 并获取该变量的地址

	string str="";
	stringstream ss;
	ss << p;
	ss >> str;      // 将变量的地址转化为字符串
	int num_1=zhuanghua(str); //得到地址转化进制后的数值
	string str_1="";
	stringstream ss_1;
	ss_1 << num_1;
	ss_1 >> str_1; //将得到的地址转化数值转化为字符串1

	string str_2="";
	stringstream ss_2;
	ss_2 << x;
	ss_2 >> str_2;//将给予了任意数值的变量转化为字符串2

	cheng(str_1, str_2);

	return 0;
}


3.1 链表

#include<stdio.h>
#include<stdlib.h>
struct num{
    int    number;
    struct num* next;
};
int main() {
    struct num* head=NULL, * tail=NULL;
    struct num *p= NULL;
    int number;
    scanf_s("%d",&number);
    while (number != 9999) {
        p = (struct num*)malloc(sizeof(struct num));
        p->number = number;
        p->next = NULL;
        if (head == NULL) {
            head = p;
        }
        else {
            tail->next = p;
        }
        tail = p;
        scanf_s("%d", &number);
    }
}
原文地址:https://www.cnblogs.com/1208712478qq/p/14303884.html