Description
Today Berland holds a lottery with a prize — a huge sum of money! There are k persons, who attend the lottery. Each of them will receive a unique integer from 1 to k.
The organizers bought n balls to organize the lottery, each of them is painted some color, the colors are numbered from 1 to k. A ball of color c corresponds to the participant with the same number. The organizers will randomly choose one ball — and the winner will be the person whose color will be chosen!
Five hours before the start of the lottery the organizers realized that for the lottery to be fair there must be an equal number of balls of each of k colors. This will ensure that the chances of winning are equal for all the participants.
You have to find the minimum number of balls that you need to repaint to make the lottery fair. A ball can be repainted to any of the kcolors.
Input
The first line of the input contains two integers n and k(1 ≤ k ≤ n ≤ 100) — the number of balls and the number of participants. It is guaranteed that n is evenly divisible by k.
The second line of the input contains space-separated sequence of n positive integers ci(1 ≤ ci ≤ k), where ci means the original color of the i-th ball.
Output
In the single line of the output print a single integer — the minimum number of balls to repaint to make number of balls of each color equal.
Sample Input
4 2
2 1 2 2
1
8 4
1 2 1 1 1 4 1 4
3
Hint
In the first example the organizers need to repaint any ball of color 2 to the color 1.
In the second example the organizers need to repaint one ball of color 1 to the color 2 and two balls of the color 1 to the color 3.
1 /************************************************************************* 2 > File Name: code/hust/20151025/I.cpp 3 > Author: 111qqz 4 > Email: rkz2013@126.com 5 > Created Time: 2015年10月25日 星期日 13时09分42秒 6 ************************************************************************/ 7 8 #include<iostream> 9 #include<iomanip> 10 #include<cstdio> 11 #include<algorithm> 12 #include<cmath> 13 #include<cstring> 14 #include<string> 15 #include<map> 16 #include<set> 17 #include<queue> 18 #include<vector> 19 #include<stack> 20 #include<cctype> 21 22 #define yn hez111qqz 23 #define j1 cute111qqz 24 #define ms(a,x) memset(a,x,sizeof(a)) 25 using namespace std; 26 const int dx4[4]={1,0,0,-1}; 27 const int dy4[4]={0,-1,1,0}; 28 typedef long long LL; 29 typedef double DB; 30 const int inf = 0x3f3f3f3f; 31 int n,k; 32 int cnt[111]; 33 34 bool cmp( int a,int b) 35 { 36 return a>b; 37 } 38 int main() 39 { 40 #ifndef ONLINE_JUDGE 41 freopen("in.txt","r",stdin); 42 #endif 43 44 scanf("%d %d",&n,&k); 45 ms(cnt,0); 46 for ( int i = 0 ; i < n ; i++) 47 { 48 int x; 49 scanf("%d",&x); 50 cnt[x]++; 51 } 52 sort(cnt,cnt+105,cmp); 53 int ans = 0 ; 54 int ave = n/k; 55 for ( int i = 0 ; i < 105 ; i++) 56 { 57 if (cnt[i]<=ave) break; 58 else ans+=cnt[i]-ave; 59 } 60 printf("%d ",ans); 61 62 63 #ifndef ONLINE_JUDGE 64 fclose(stdin); 65 #endif 66 return 0; 67 }