java数组实现红包的方法

 1 package Hongbao;
 2 
 3 import java.text.DecimalFormat;
 4 import java.util.Scanner;
 5 
 6 public class Hongbao {
 7     public static void main(String[] args) {
 8         Scanner sc=new Scanner(System.in);
 9         
10         System.out.println("请输入红包金额：");
11         double money=sc.nextDouble();
12         
13         System.out.println("请输入红包个数：");
14         int count=sc.nextInt();
15         
16         //有序数组1到99
17         int[] num=new int[100];
18         for (int i = 1; i < 100; i++) {
19             num[i-1]=i;
20         }
21         
22         //有序数组打乱
23         for (int i = 0; i < num.length; i++) {
24             int ran=(int)(Math.random()*100);
25             int temp=num[i];
26             num[i]=num[ran];
27             num[ran]=temp;
28         }
29         
30         //将分配的红包个数赋给新数组
31         int[] acount=new int[count];
32         for (int i = 0; i < count; i++) {
33             acount[i]=num[i]; 
34         }
35         //冒泡排序
36         for (int i = 0; i < acount.length; i++) {
37             for (int j = 0; j < acount.length-1-i; j++) {
38                 if(acount[j]>acount[j+1]){
39                   int temp=acount[j];
40                   acount[j]=acount[j+1];
41                   acount[j+1]=temp;
42                 }
43             } 
44         }
45             
46         //红包分钱算法
47         int[] mon=new int[count];
48         for (int i = 0; i < count; i++) {
49             if(i==0){
50                 mon[0]=acount[0];
51             }else if(i>0&&i<count-1){
52                 mon[i]=acount[i]-acount[i-1];
53             }else{
54                 mon[i]=100-acount[i-1];
55             }
56         }
57 
58         //带钱
59         DecimalFormat df=new DecimalFormat("####0.00");//保留两位小数
60         for (int i = 0; i < mon.length; i++) {
61             System.out.println("第"+(i+1)+"名，领取"+df.format(mon[i]*0.01*money)+"元红包");
62         }
63         
64     }
65 }