LeetCode OJ:ZigZag Conversion(字符串的Z字型转换)

The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P   A   H   N
A P L S I I G
Y   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

将字符进行Z字型转换,然后进行存储,一开始没有想到什么好方法,看了下别人的实现,可以做的比较简单,每一行用一个字符串记录下来之后,然后拼接起来就可以,非满列字符串是有规律的,具体见下代码:

 1 class Solution {
 2 public:
 3     string convert(string s, int numRows) {
 4         vector<string> res;
 5         res.resize(numRows);
 6         string ret;
 7         int gap = numRows - 2;
 8         int i = 0, j;
 9         while(i < s.size()){
10             for(j = 0; i < s.size() && j < numRows; ++i, ++j)
11                 res[j] += s[i];
12             for(j = gap; i < s.size() && j > 0; ++i, --j)
13                 res[j] += s[i];
14         }
15         for(int k = 0; k < numRows; ++k){
16             ret += res[k];
17         }
18         return ret;
19     }
20 };
原文地址:https://www.cnblogs.com/-wang-cheng/p/4942911.html