poj 1256 Anagram

按要求排序,然后调用next_permutation即可。

#include<iostream>
#include<algorithm>
#include<cstring>

using namespace std;


bool cmp(const char &a, const char &b)
{
	if(a <= 'Z' && a >= 'A' && b <= 'Z' && b >= 'A')
		return a < b;
	if(a <= 'z' && a >= 'a' && b <= 'z' && b >= 'a')
		return a < b;
	if(a <= 'Z' && a >= 'A' && b <= 'z' && b >= 'a')
		return a + 32 <= b;
	if(a<='z' && a >='a' && b <= 'Z' && b >= 'A')
		return a < (b + 32);
}

int main()
{
	int num = 0;
	cin >> num;
	while(num--)
	{
		char str[100];
		cin >> str;
		int length = strlen(str);
		sort(str, str+length, cmp);
		cout << str << endl;
		while(next_permutation(str, str + length, cmp))
		{
			cout << str << endl;
		}
	}
	return 0;
}


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原文地址:https://www.cnblogs.com/wanglaoda/p/4937123.html