js知识点~扁平数据结构转Tree

1、查看扁平数据以及输出结果:

扁平数据结构如下:

  

let arr = [
    {id: 1, name: '部门1', pid: 0},
    {id: 2, name: '部门2', pid: 1},
    {id: 3, name: '部门3', pid: 1},
    {id: 4, name: '部门4', pid: 3},
    {id: 5, name: '部门5', pid: 4},
]

 输出结果数据:

[
    {
        "id": 1,
        "name": "部门1",
        "pid": 0,
        "children": [
            {
                "id": 2,
                "name": "部门2",
                "pid": 1,
                "children": []
            },
            {
                "id": 3,
                "name": "部门3",
                "pid": 1,
                "children": [
                    // 结果 ,,,
                ]
            }
        ]
    }
]

2、以上例子的几种解决方案

  1> 主要思路也是先把数据转成Map去存储,之后遍历的同时借助对象的引用,直接从Map找对应的数据做存储。不同点在遍历的时候即做Map存储,有找对应关系。

function arrayToTree(items) {
  const result = [];   // 存放结果集
  const itemMap = {};  // 
  for (const item of items) {
    const id = item.id;
    const pid = item.pid;

    if (!itemMap[id]) {
      itemMap[id] = {
        children: [],
      }
    }

    itemMap[id] = {
      ...item,
      children: itemMap[id]['children']
    }

    const treeItem =  itemMap[id];

    if (pid === 0) {
      result.push(treeItem);
    } else {
      if (!itemMap[pid]) {
        itemMap[pid] = {
          children: [],
        }
      }
      itemMap[pid].children.push(treeItem)
    }

  }
  return result;
}
View Code

  2> 主要思路是先根据pid进行由大到小排序之后,循环数据进行填充children,最后过滤数据第一级

function arrToTree(arr) {
 arr
 .sort((a, b) => b.pid - a.pid)
 .forEach((v) => {
 const pan = arr.filter((g) => g.id === v.pid)[0] || {};
 if (pan['children']) {
 pan['children'].push(v);
 } else {
 pan['children'] = [v];
 }
 
 });
 return arr.filter(v => v.pid === 0)
}
arrToTree(arr);
View Code

 

  3> 与第一种方法类似,主要思路也是先把数据转成Map去存储,之后遍历的同时借助对象的引用,直接从Map找对应的数据做存储。更精简(推荐)

function ArrayToTree(array) {
 array = JSON.parse(JSON.stringify(array))
 let result = []
 let trees = {}
 array.forEach(item => {
 item.children = []
 trees[item.id] = item
 })
 array.forEach(item => {
 if(trees[item.pid]) trees[item.pid].children.push(item)
 if(item.pid == 0) result.push(item)
 })
 return result;
}
ArrayToTree(arr)
View Code
原文地址:https://www.cnblogs.com/songmeiling/p/15010914.html