codeforces #322 div 2 A. Vasya the Hipster(随便搞)

A. Vasya the Hipster
time limit per test
1 second
memory limit per test
256 megabytes
input
standard input
output
standard output

One day Vasya the Hipster decided to count how many socks he had. It turned out that he had a red socks and b blue socks.

According to the latest fashion, hipsters should wear the socks of different colors: a red one on the left foot, a blue one on the right foot.

Every day Vasya puts on new socks in the morning and throws them away before going to bed as he doesn't want to wash them.

Vasya wonders, what is the maximum number of days when he can dress fashionable and wear different socks, and after that, for how many days he can then wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.

Can you help him?

Input

The single line of the input contains two positive integers a and b (1 ≤ a, b ≤ 100) — the number of red and blue socks that Vasya's got.

Output

Print two space-separated integers — the maximum number of days when Vasya can wear different socks and the number of days when he can wear the same socks until he either runs out of socks or cannot make a single pair from the socks he's got.

Keep in mind that at the end of the day Vasya throws away the socks that he's been wearing on that day.

Sample test(s)
input
3 1
output
1 1
input
2 3
output
2 0
input
7 3
output
3 2
Note

In the first sample Vasya can first put on one pair of different socks, after that he has two red socks left to wear on the second day.

实在没有可以解释的...

 1 /*************************************************************************
 2     > File Name: code/cf/#322/A.cpp
 3     > Author: 111qqz
 4     > Email: rkz2013@126.com 
 5     > Created Time: 2015年09月29日 星期二 00时14分24秒
 6  ************************************************************************/
 7 
 8 #include<iostream>
 9 #include<iomanip>
10 #include<cstdio>
11 #include<algorithm>
12 #include<cmath>
13 #include<cstring>
14 #include<string>
15 #include<map>
16 #include<set>
17 #include<queue>
18 #include<vector>
19 #include<stack>
20 #include<cctype>
21 #define y1 hust111qqz
22 #define yn hez111qqz
23 #define j1 cute111qqz
24 #define ms(a,x) memset(a,x,sizeof(a))
25 #define lr dying111qqz
26 using namespace std;
27 #define For(i, n) for (int i=0;i<int(n);++i)  
28 typedef long long LL;
29 typedef double DB;
30 const int inf = 0x3f3f3f3f;
31 int main()
32 {
33   #ifndef  ONLINE_JUDGE 
34   // freopen("in.txt","r",stdin);
35   #endif
36     int a,b;
37     cin>>a>>b;
38     int tmp = min(a,b);
39     cout<<tmp<<" ";
40     if (a>b)
41     {
42     cout<<(a-b)/2<<endl;
43     }
44     else
45     {
46     cout<<(b-a)/2<<endl;
47     }
48 
49    
50  #ifndef ONLINE_JUDGE  
51   fclose(stdin);
52   #endif
53     return 0;
54 }
View Code
原文地址:https://www.cnblogs.com/111qqz/p/4845375.html